Guess my Robot

Hi, this is Mitty. Your sequence, Yishay, reminds me our sequence on the picture from the webreport on the harmonic series and the robots. Only, we had a mistake in the first term (in ohut case it was written 5 on the board).

by adding up consecutive members of the sequence {1/n} we obsurve how many terms are necessary to "jump over" 2, 3, 4, etc. So in your case we need 4 members (1+1/2+1/3+1/4) to "jump over" 2; then we need 11 terms to "jump over" 3; we need 31 terms to "jump over" 4, etc. These numbers are somehow "unhandy" and I can't think of a formula. When I and Teddy built robots to generate this sequence we set a limit starting from 2 and then changed it by hand.

Even with the team of robots George built one has to wait for  a very long time in order to get the next terms of the sequence.

I am curious to see if one has come up with a better idea. 

Replies to this comment

I have a conjecture... (Posted by Sofia at 25-02-05)